Penjelasan dengan langkah-langkah:
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[tex]\tt x^2 + 3x + 2 = 0[/tex]
[tex]\sf a = 1, \: b = 3, \: c = 2[/tex]
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Gunakan rumus kuadratik
[tex]\boxed{\sf x = \frac{- b ± \sqrt{b^2 - 4ac}}{2a}}[/tex]
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Evaluasi
[tex]\displaystyle \sf x = \frac{- 3 ± \sqrt{3^2 - 4 \times 1 \times 2}}{2 \times 1}[/tex]
[tex]\displaystyle \sf x = \frac{-3 ± \sqrt{9 - 8}}{2}[/tex]
[tex]\displaystyle \sf x = \frac{-3 ± \sqrt{1}}{2}[/tex]
[tex]\displaystyle \sf x = \frac{-3 ± 1}{2}[/tex]
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Nilai x1
[tex]\displaystyle \sf x_1 = \frac{-3 + 1}{2}[/tex]
[tex]\displaystyle \sf x_1 = \frac{-2}{2}[/tex]
[tex]\sf x_1 = - 1[/tex]
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Nilai x2
[tex]\displaystyle \sf x_2 = \frac{-3 - 1}{2}[/tex]
[tex]\displaystyle \sf x_2 = \frac{-4}{2}[/tex]
[tex]\sf x_2 = - 2[/tex]
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Penyelesaian
[tex]\boxed{\bf x_1 = -1, \: x_2 = -2}[/tex]
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